[gpaw-users] How can the vacuum potential be found out
Georg Kastlunger
georg.kast at hotmail.com
Tue Feb 7 14:23:18 CET 2012
Dear Jens Jørgen,
Thank you very much for your help.
Now everything seems to be clear!
Best regards,
Georg Kastlunger
On 02/07/2012 08:11 AM, Jens Jørgen Mortensen wrote:
> On 06-02-2012 17:30, Georg Kastlunger wrote:
>>
>>
>>
>>
>>
>>
>>
>>
>>
>> Thanks again for your help,
>> but unfortunately we are primarily interested in the case of periodic
>> boundary conditions.
>>
>> Is there maybe anybody else who might know how the zero energy is
>> defined in periodic cells?
>
> For that case, the average of the Coulomb potential is zero, where the
> Coulomb potential is the potential we get from solving the Poisson
> equation "nabla v_coulomb=4 pi rho", where rho is the pseudo charge
> density. The total effective potential is the v_coulomb+v_XC.
>
> Jens Jørgen
>
>> Regards,
>> Georg
>>
>>
>> On 02/06/2012 05:22 PM, Ask Hjorth Larsen wrote:
>> > Hi
>> >
>> > On Mon, 6 Feb 2012, Georg Kastlunger wrote:
>> >
>> >> Which boundary do you mean?
>> >> Is it the value at one certain point in the cell or an average of an
>> >> interface between unit cells?
>> >>
>> >> Best regards,
>> >> Georg
>> >
>> > The potential is zero at all the non-periodic cell boundaries. This
>> > means one cannot shift the potential arbitrarily - it is unique, and
>> > so are the eigenvalues.
>> >
>> > Each eigenvalue equals the derivative of the total energy with respect
>> > to the occupation of the corresponding state (keeping wavefunctions
>> > and density constant).
>> >
>> > (The same is not true if the cell is fully periodic; then I'm not sure
>> > what determines the potential and eigenvalues)
>> >
>> > Regards
>> > Ask
>> >
>> >
>>
>
>
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